{
	"Math_QuickPow": {
		"prefix": "Math_QuickPow",
		"body": [
			"",
			"ll quick_Pow(ll a, ll b, ll mod) {",
			"  // a的b次方模mod",
			"  ll res = 1, t = a;",
			"  while (b) {",
			"    if (b & 1) res = (res * t) % mod;",
			"    t = t * t % mod;",
			"    b >>= 1;",
			"  }",
			"  return res;",
			"}",
			"",
		],
	},
	"Math_Fm": {
		"prefix": "Math_Fm",
		"body": [
			"",
			"ll quick_Pow(ll a, ll b, ll mod) {",
			"  // a的b次方模mod",
			"  ll res = 1, t = a;",
			"  while (b) {",
			"    if (b & 1) res = (res * t) % mod;",
			"    t = t * t % mod;",
			"    b >>= 1;",
			"  }",
			"  return res;",
			"}",
			"",
			"ll Fm(ll a, ll mod) {",
			"  //费马小定理求逆元",
			"  return quick_Pow(a, mod - 2, mod);",
			"}",
			"",
		],
	},
	"Math_C": {
		"prefix": "Math_C",
		"body": [
			"",
			"ll quick_Pow(ll a, ll b, ll mod) {",
			"  // a的b次方模mod",
			"  ll res = 1, t = a;",
			"  while (b) {",
			"    if (b & 1) res = (res * t) % mod;",
			"    t = t * t % mod;",
			"    b >>= 1;",
			"  }",
			"  return res;",
			"}",
			"",
			"ll Fm(ll a, ll mod) {",
			"  //费马小定理求逆元",
			"  return quick_Pow(a, mod - 2, mod);",
			"}",
			"",
			"ll C(ll n, ll m, ll mod) {",
			"  ll fz = 1, fm = 1;",
			"  for (ll i = n; i >= n - m + 1; i--) fz = fz * i % mod;",
			"  for (ll i = 1; i <= m; i++) fm = fm * i % mod;",
			"  return (fz * Fm(fm, mod)) % mod;",
			"}",
			"",
		],
	},
	"Class_Math_Bignum": {
		"prefix": "Class_Math_Bignum",
		"body": [
			"",
			"class Math_Bignum {",
			" public:",
			"  string Bignum;",
			"",
			"  vll num;",
			"",
			"  Math_Bignum(string s) {",
			"    Bignum = s;",
			"    for (auto i : s) num.push_back(i - '0');",
			"  }",
			"",
			"  Math_Bignum(vll v) {",
			"    string s;",
			"    num = v;",
			"    for (auto i : v) s.push_back(i + '0');",
			"  }",
			"",
			"  Math_Bignum(ll l) {",
			"    string s;",
			"    while (l) s.push_back(l % 10 + '0'), num.push_back(l % 10), l /= 10;",
			"    reverse(num.begin(), num.end());",
			"    reverse(s.begin(), s.end());",
			"    Bignum = s;",
			"  }",
			"",
			"  ll get(ll l, ll r) {",
			"    ll res = 0;",
			"    for (int i = l - 1; i <= r - 1; i++) res = res * 10 + num[i];",
			"    return res;",
			"  }",
			"};",
			"",
		],
	},
}